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2 years ago

Driving cars lowers the ph of the oceans by what?

Chemistry

2 answers:

Hatshy [7]2 years ago

4 0

Answer: Ocean acidification

Explanation:

Driving cars can lower the pH of ocean by release of carbon dioxide in the environment. The release of carbon dioxide in the environment gets diffused in the water and increases the pH of water.

The carbon dioxide gets dissolved in water and forms carbonic acid which is harmful for the aquatic animals as it degrades their shells and can kill aquatic animals.

hence, the answer is ocean acidification.

grin007 [14]2 years ago

3 0

A. releassing Co2 that dissolves and forms acid in the oceans

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lara [203]

Answer: 1. HYDROCARBONS? 2. ALKANES?

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2 years ago

What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?

leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

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2 years ago

The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28

ivanzaharov [21]

Answer: The mass of second isotope of indium is 114.904 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

For isotope 1:

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

For isotope 2:

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

Hence, the mass of second isotope of indium is 114.904 amu

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2 years ago

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IrinaVladis [17]

Answer:

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Explanation:

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2 years ago

Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:

aliya0001 [1]

Answer:

Explanation:1. NaNH2 (1-Butene)

CH3CH2CH2CH2Cl --------------> CH3CH2CH=CH2 + HCl (elimination reaction)

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2 years ago