Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2
tan(J)=4.tan(R)
option D
Answer:
For the domain indicated, the range is {-11, -7, -3, 1, 5}
Step-by-step explanation:
Given the indicated domain of f(x) you have to replace the values in the function to find the range (the "y" values of the function).
f(-2) = 5
f(0) = 1
f(2) = -3
f(4) = -7
f(6) = -11.
So the range for this domain is {-11, -7, -3, 1, 5}
Answer: 13y (y+5)
Step-by-step explanation:
Hello,
Answer A is the only finite set.
Answer:
y=a(x+4)^2 +1, for a real number a hat is different of 0.
Step-by-step explanation:
If we know only the vertex, there are many quandratic equations.
* Result: Vertex (m,n), the quadratic equation is y= a(x-m)^2 + n for a real number a that is different of 0.
Here, the vertex (-4,1), we have the equation: y=a(x+4)^2 +1, for a real number a hat is different of 0.
Hope you understand.