Check the picture below.
Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
1 answer:
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y =
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 =
Cancel the C in both side
1/2 =
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
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Answer:
376 square centimeters
Step-by-step explanation:
When doubled, the new length is 5*2=10 cm, new width is 4*2=8 cm, and new height is 3*2=6 cm.
The surface area of a rectangular prism is given by :
Where l is length, w is width, and h is height
Plugging in the new values we get:
The surface area of the enlarged prism = 376 cm^2