Answer:
3c + 12
Step-by-step explanation:
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
2
Step-by-step explanation:
Answer:B
I think we are in the same class lol
Step-by-step explanation:448 divided by 14= 32
448 divided by 16= 28
B=speed of boat in water
Y= Speed of current
B+y=32
B-y=28
32 + 28 =60
60 divided by 2 = 30
32 -30 =2
B=30
Y=2
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