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2 years ago

The value of x is 4 times the value of y.how to writ that in math

1 answer:

3 0

I’m not exactly sure what you mean by “write it in math,” however I can tell you what I think.
4y=x
(It says that x is 4 times the value of y which means that y times 4 is x.)

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The graph of y = 3x - 4 is shown. Use it to solve the equation 3x - 4 = 2.

Cloud [144]

Answer:

The answer is 2

Step-by-step explanation:

3(2) - 4= 2

6 - 4= 2

2=2

5 0

2 years ago

4 2/5 divided by 1 1/3

Naddik [55]

Answer:

3.3

Step-by-step explanation:

$= > \frac{4 \frac{2}{5} }{1 \frac{1}{3} } \\ \\ = > \frac{ \frac{20 + 2}{5} }{ \frac{3 + 1}{3} } \\ \\ = > \frac{ \frac{22}{5} }{ \frac{4}{3} } \\ \\ = > \frac{22}{5} \times \frac{3}{4} \\ \\ = > \frac{11}{5} \times \frac{3}{2} \\ \\ = > \frac{33}{10} \\ \\ = > 3.3$

6 0

2 years ago

A baker decorates 42 cupcakes in 30 minutes.She decorates cupcakes at a constant rate.

NikAS [45]

Answer:

Step-by-step explanation:

Well the way i said it was

42-30= 12

altho i not very sure

3 0

2 years ago

Acellus

mylen [45]

Answer: 90degrees

Step-by-step explanation: The question was asked in degree. So the answer should be in degree. Which leaves us with no option than 90degrees.

8 0

2 years ago

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

Zanzabum

Answer:

a) (1215, 1297)

b) (1174, 1338)

c) (1133, 1379)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

Also known as 68-95-99.7 rule.
It states that almost all the data lies within three standard deviation for a normal data.
About 68% of data lies within 1 standard deviation of mean.
About 95% of data lies within two standard deviation of mean.
About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

$\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)$

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

$\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)$

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

$\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)$

All of data will be found between 1133 years and 1379 years.

3 0

3 years ago