Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
Answer: a = 15
Step-by-step explanation:
6a + 10 = 3a + 55
Subtract 10 from both sides
6a = 3a + 45
Subtract 3a from both sides
3a = 45
Divide each side by 3
a = 15
Given:
Circular racetrack with a diameter of 1/2 mile
Find: how far does a car travel in one lap around the track?
We need to find the circumference of the racetrack.
Circumference is multiplying pi to the diameter of the racetrack.
Circumference = 3.14 * 1/2 mile
Circumference = 3.14/2 mile
Circumference = 1.57 miles rounded to the nearest tenth is 1.60 miles.
Answer:
Is this the full question?
here we have to find the quotient of '(16t^2-4)/(8t+4)'
now we can write 16t^2 - 4 as (4t)^2 - (2)^2
the above expression is equal to (4t + 2)(4t - 2)
there is another expression (8t + 4)
the expression can also be written as 2(4t + 2)
now we have to divide both the expressions
by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)
therefore the quotient is (4t - 2)/2
the expression comes out to be (2t - 1)
