It's B the atom has 4 neutrons and 4 protons because atom can be completed through the existence of neutron and proton which stay inside of the neuclues of atom
The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
<h3>Molarity of diluted solution (M₂) =....? </h3>
The molarity of the diluted solution can be obtained as follow:
<h3>M₁V₁ = M₂V₂</h3>
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
<h3>Divide both side by 3250</h3><h3 />
M₂ = 1050 / 3250
<h3>M₂ = 0.32 M</h3>
Therefore, the molarity of the diluted solution is 0.32 M
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I think its mass of volume
I think the answer is <span>PCl5 + 4H2O → 5HCl + H3PO4
</span>
The answer for the following problem is mentioned below.
- <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are 19.3 × 10^23 molecules.</em></u>
Explanation:
Given:
mass of calcium phosphate (
) = 125.3 grams
We know;
molar mass of calcium phosphate ( ) = (40×3) + 3 (31 +(4×16))
molar mass of calcium phosphate ( ) = 120 + 3(95)
molar mass of calcium phosphate ( ) = 120 +285 = 405 grams
<em>We also know;</em>
No of molecules at STP conditions(
) = 6.023 × 10^23 molecules
To solve:
no of molecules present in the sample(N)
We know;
N÷
=
N =(405×6.023 × 10^23) ÷ 125.3
N = 19.3 × 10^23 molecules
<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are 19.3 × 10^23 molecules</em></u>
