Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;
The n'th term of a Arithmetic Sequence let's say it be is given by ;
Where , <u>d</u> is the common difference
Now , here we are given with ;
We have to find the 2nd , 3rd and 4th term respectively ,
Now , by using the above formula , 5th term can be written as ;
Putting the values and transposing 1st term to RHS , we have ;
Now , as we got the common difference , so we can find out the missing terms now ;
Now
Also ,
Now , The given table can be written as ;
Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;
brainly.com/question/26750175
You are supposed to use the third option: 3n2 + 6n + 5 = 116.
Take a look at the attachment to see how I got that solution.
Hope it helps! :)
Answer:
option A is the answer hope you find it helpful
Answer:
odd
Step-by-step explanation:
Just so you know there are shortcuts for determining if a polynomial function is even or odd. You just to make sure you use that x=x^1 and if you have a constant, write it as constant*x^0 (since x^0=1)
THEN!
If all of your exponents are odd then the function is odd
If all of your exponents are even then the function is even
Now you have -4x^3+4x^1
3 and 1 are odd it is an odd function
This a short cut not the legit algebra way
let me show you that now:
For it to be even you have f(-x)=f(x)
For it be odd you have f(-x)=-f(x)
If you don't have either of those cases you say it is neither
So let's check
plug in -x -4(-x)^3+4(-x)=-4*-x^3+-4x=-4x^3+-4x
that's not the same so not even
with if we factor out -1 .... well if we do that we get -(4x^3+4x)=-f(x)
so it is odd.
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