Hey its p(A) = 0.1 and q(a) = 0.9
The percentage in the population of heterozygous
individuals:
2pq = 2 x 0.1 x 0.9 = 0.18 = 18%
Answer: Aldolase
Explanation:
In the metabolism of glucose( glycolysis) phosphofructokinase is an enzyme that catalyzes the conversation of fructose-6-phosphate into fructose-1,6-bisphosphate. This in turn is converted to pyruvate after various steps of enzymatic activity in the glycolytic pathway.
If phosphofructokinase experienced a mutation that interfered with substrate binding, the enzyme that is going to be most immediately impacted in terms of accessing substrate is the ALDOLASE.
Aldolase enzymes cleave fructose-1,6-bisphosphate to triose phosphates( glyceraldehyde 3-phosphate and dihydroxy-acetone phosphate) facilitating an increase in anaerobic production of ATP in muscle.
Therefore, the substrate for binding of aldolase, which is fructose-1,6-bisphosphate is lacking due to mutation of phosphofructokinase enzyme.
A negative correlation is most clearly seen between different levels of female education and the total fertility rate (TFR) in a population. TFR is the number of children a woman can expect to have over her lifetime given current rates of age-specific fertility.
Hope i answered right!!!