Calculate the ph of the solution that results following addition of 24 ml of 1.0 mnaoh to 60 ml of 1.0 mnh4cl.
1 answer:
The pH of the solution is 0.37.
<h3>What is the pH of the solution?</h3>We can write the equation of the reaction as;
Number of moles of = 24/1000 * 1 = 0.024 moles
Number of moles of = 60/1000 * 1 = 0.060 moles
Given that the reaction is 1:1, the limiting reactant is NaOH
Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles
Concentration of left over NH4Cl = 0.036 moles/(24 + 60)/1000
= 0.43 moles
pH = -log(0.43)
pH = 0.37
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