Answer:
ΔS° = 180.5 J/mol.K
Explanation:
Let's consider the following reaction.
4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)
The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.
ΔS° = ∑np × S°p - ∑nr × S°r
where,
ni are the moles of reactants and products
S°i are the standard molar entropies of reactants and products
ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))
ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol
ΔS° = 180.5 J/K
This is the change in the entropy per mole of reaction.
We could use solar power, wind power, geothermal power, hydroelectric power, or nuclear power. There are probably more but this is what I can think of off the top of my head. I hope this helps. Let me know if anything is unclear.
In every direction guyz but conventionally it moves from higher potential to lower potential
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
The answer is going to be hydrochloric acid, therefore hydrochloric acid is a binary acid.
