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8 months ago

You want to average 90 km/h on a car trip. You cover the first half of the distance at an

Physics

1 answer:

bogdanovich [222]8 months ago

4 0

(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.

(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.

<h3>What is average velocity?</h3>

Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

average velocity = total distance / total time

v = (d)/(0.5d/v₁ + 0.5d/v₂)

where;

v is the average velocity
v₁ is the average velocity during the first half
v₂ is the average velocity during the second half

90 km/h = (d) / (0.5d/48 + 0.5d/v₂)

90(0.5d/48 + 0.5d/v₂) = d

0.9375d + 0.5d/v₂ = d

d(0.9375 + 0.5/v₂) = d

0.9375 + 0.5/v₂ = 1

0.5/v₂ = 0.0625

v₂ = 0.5/0.0625

v₂ = 8 km/h

Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.

The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.

Learn more about average velocity here: brainly.com/question/24739297

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