Answer:
F = - K x
a) K = 1.3 kg * 9.8 m/s^2 / .096 m = 133 kg/sec^2
b) ω = (K/m)^1/2 angular frequency of SHM
ω = (133 / 1.3)^1/2 = 10.1 / sec
f = 2 π ω = 6.28 * 10.1 / sec = 63.5 / sec
P = 1/f = .0157 sec
Answer: Rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.
Explanation: Terminal velocity is defined as the final velocity attained by an object falling under the gravity. At this moment weight is balanced by the air resistance or drag force and body falls with zero acceleration i.e. with a constant velocity.
Case 1: Terminal velocity of a piece of tissue paper.
The weight of tissue paper is very less and it experiences an air resistance while falling downward under the effect of gravity.
Downward gravitational force, F = mg
Upward air resistance or friction or drag force will be
So, paper will attain terminal velocity when mg =
Case 2: Rock is very heavy and require larger air resistance to balance the weight of rock relative to the tissue paper case.
Downward force on rock, F = Mg
Drag force =
Rock will attain terminal velocity when Mg =
Mg > mg
so, >
And rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.
Answer:
Part a)
Part b)
Part c)
Part d)
Net force on a closed loop in uniform magnetic field is always ZERO
Explanation:
As we know that force on a current carrying wire is given as
now we have
Part a)
current in side 166 cm and magnetic field is parallel
so we have
here we know that L and B is parallel to each other so
Part b)
For 68.1 cm length wire we have
here we know that
so we have
Part c)
For 151 cm length wire we have
here we know that
so we have
Part d)
Net force on a closed loop in uniform magnetic field is always ZERO
Answer:
The deflection of the spring is 34.56 mm.
Explanation:
Given that,
Diameter = 10 mm
Number of turns = 10
Load = 200 N
We need to calculate the deflection
Using formula of deflection
Put the value into the formula
Hence, The deflection of the spring is 34.56 mm.
2 is sedimentary and 3 is metamorphic