Answer:
The vector joining the ship to the rock is t= 7 i + 5 j
The direction is 0.9505 radians east of north.
Step-by-step explanation:
The position vector of the ship:
r= 1 i + 0 j
The position vector of the ship:
s= 6 i + 5 j
The vector joining the ship to the rock is:
t = r + s
t = (1 i + 0 j) + (6 i + 5 j)
t = 7 i + 5 j
The bearing of the rock to the ship is:
Θ= = 0.9505 radians
The answer should probably be 2627.1 feet
Hope this helps!
Answer:
1,536 square centimeters
Step-by-step explanation:
The formula for the Lateral surface area of the pyramid =
1/2 × perimeter of the square base × slant height
Square base = 32cm
Slant height = 24cm
Perimeter of the square base = (4 × length of the square base side)
4 × 32cm = 128cm
Lateral Surface Area = 1/2 × 128cm × 24cm
= 1,536 square centimeters
Answer:
P = 32
x = 35
Step-by-step explanation:
For the first diagram,
The two angles given are corresponding angles. Corresponding angles are equal;
So;
the first angle is a right angle triangle;
90 = 3P - 6
3P = 90 + 6
3P = 96
P = 32
For the second diagram;
The sum of those two angles is 180°
(x + 75) + 2x = 180
x + 2x + 75 = 180
3x + 75 = 180
3x = 180 - 75
3x = 105
x = 35
<span>The topic of decimals, and patterns of decimals, seems to be of slightly greater interest to GMAC in the GMAT OG13e than in previous editions. What decimals terminate? What decimals repeat? In this post, we’ll take a look at these questions.</span>