Answer:
Conclusion:
Step-by-step explanation:
Given
We know that the diagonals of a parallelogram bisect each other.
Therefore,
Given RT = x and TP = 5x-28, so
x = 5x-28
5x = x+28
5x-x = 28
4x = 28
divide boh sides by 4
4x/4 = 28/4
x = 7
Thus, the value of x = 7
Similarly,
QT = TS
Given QT = 5y and TS = 2y+12, so
5y = 2y+12
5y-2y = 12
3y = 12
divide both sides by 3
3y/3 = 12/3
y = 4
Thus, the value of y = 4
Conclusion:
Answer:
nevermind, i figured it out!
<10 = 92
<8 = 92
<9 = 88
<5 = 106
<11 = 106
<13 = 106
yes these are actually the answers, lol
Step-by-step explanation:
Answer:
m∠ABD = m∠CBE ⇒ by subtracting a common angle from the given angles
Step-by-step explanation:
∵ m∠ABE = m∠CBD
∵ m∠ABD = m∠ABD + m∠DBE
∵ m∠CBD = m∠CBE + m∠EBD
∵ ∠EBD is common angle between them
∴ m∠ABD = m∠CBE
