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1 year ago

The longer the time between the arrival of the P-wave and S-wave, the _______ is the epicenter.

Physics

1 answer:

Brrunno [24]1 year ago

7 0

The longer the time between the arrival of the P-wave and S-wave, the farther away is the epicenter.

<h3>What is epicenter and the relation between P-wave and S-wave?</h3>

The point on the earth's surface vertically above the hypocenter (or focus), point in the crust where a seismic rupture begins is said to be epicenter.
There are two types of waves during earthquakes, they are:

P - wave
S - wave

Each seismograph records the times when the first (P waves) and second (S waves) seismic waves arrive.
From the graph, through the information, scientists can determine how fast the waves are traveling.
The longer the time between the arrival of the P-wave and S-wave, the farther away is the epicenter.

Hence, Option B is the correct answer.

Learn more about epicenter,

brainly.com/question/28136716

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2 years ago

A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

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71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

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