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1 year ago

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PLEASE HELPPPP !!!! Scientific investigations must be well ____ to be sure the data collected will help answer the scientists qu

estion IT IS DUE BY TOMORROW

1 answer:

konstantin123 [22]1 year ago

3 0

Answer-

Analyzed or conducted

Hope this helped

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Five grams of sugar is dissolved in 50 grams of water what is the mass of the water

tangare [24]

The mass of the water with the sugar dissolved in it is 55 grams. This is because when you add the weight of the water, and the sugar that you added, it is 55.

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3 years ago

Read 2 more answers

The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to c

Korolek [52]

Answer: C) divide: distance ÷ velocity

Explanation:

The velocity $V$ equation is distance $d$ divided by time $t$ :

$V=\frac{d}{t}$

If we isolate $t$ we will have:

$t=\frac{d}{V}$

Hence, the correct option is C: distance divided by velocity.

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2 years ago

How much heat must be added to make a 5g substance with a specific heat of 2 J/gC that has its temperature go up 10 degrees? Q =

zlopas [31]

Answer:

100 Joule

Explanation:

Amount of heat in agiven body is given by Q = m•C•ΔT

where m is the mass of the body

c is the specific heat capacity of body. It is the amount of heat stored in 1 unit weight of body which raises raises the temperature of body by 1 unit of temperature.

ΔT is the change in the temperature of body

___________________________________________

coming back to problem

m = 5g

C = 2J/gC

since, it is given that temperature of body increases by 10 degrees, thus

ΔT = 10 degrees

Using the formula for heat as given

Q = m•C•ΔT

Q = 5* 2 * 10 Joule= 100 Joule

Thus, 100 joule heat must be added to a 5g substance with a specific heat of 2 J/gC to raise its temperature go up by 10 degrees.

8 0

2 years ago

Suppose that a comet that was seen in 550 A.D. by Chinese astronomers was spotted again in year 1941. Assume the time between ob

pickupchik [31]

To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.

Kepler's third law tells us that

$T^2 = \frac{4\pi^2}{GM}a^3$

Where

T= Period

G= Gravitational constant

M = Mass of the sun

a= The semimajor axis of the comet's orbit

The period in years would be given by

$T= 1941-550\\T= 1391y(\frac{31536000s}{1y})\\T=4.3866*10^{10}s$

PART A) Replacing the values to find a, we have

$a^3= \frac{T^2 GM}{4\pi^2}$

$a^3 = \frac{(4.3866*10^{10})^2(6.67*10^{-11})(1.989*10^{30})}{4\pi^2}$

$a^3 = 6.46632*10^{39}$

$a = 1.86303*10^{13}m$

Therefore the semimajor axis is $1.86303*10^{13}m$

PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by

$R = a(1-e)$

$R = 1.86303*10^{13}(1-0.997)$

$R= 5.58*10^{10}m$

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2 years ago

What force is required to move an object 8 m using 24 j of work?

Anna35 [415]

Answer:

3N

Explanation:

Workdone = F x d

F = force

d = distance 8m

Workdone = 24J

24 = F x 8

Divide both sides by 8

24/8 = F x 8/8

3 = F

F = 3N

7 0

2 years ago