If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Answer:
m8 its (3x)^1/2
Step-by-step explanation:
Answer:
<em>C. 6 ⋅ 9 + 1 </em>
Step-by-step explanation:
Start with the multiplication:
"one more than the product of six and nine"
6 ⋅ 9
Now take care of the addition by adding 1 to the product.
"one more than the product of six and nine"
6 ⋅ 9 + 1
Answer: C. 6 ⋅ 9 + 1
B is the answer I chose but there are the steps so you can see how to solve it
