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1 year ago

To the nearest dollar, what does the analyst believe

Mathematics

1 answer:

ruslelena [56]1 year ago

3 0

The analyst believes the value of the stock at the end of three weeks will be $134.

<h3>What are stocks?</h3>

Stock (also known as capital stock) in finance refers to the shares of ownership in a corporation or company.
A single share of stock represents fractional ownership of the corporation based on the total number of shares.
This typically entitles the shareholder (stockholder) to that fraction of the company's earnings, proceeds from asset liquidation (after discharge of all senior claims such as secured and unsecured debt), or voting power, which are often divided in proportion to the amount of money invested by each stockholder.

To find the value of the stock:

Because the stock price drops by 28% every week, it will be:
100 - 28 = 72% every week.
So, r = 0.72.
Then, the equation V = 360(r)∧t will be V = 360(0.72)∧t .
After 3 weeks, V = 360(0.72)³ = 134.47 = 134

Therefore, the analyst believes the value of the stock at the end of three weeks will be $134.

Know more about stocks here:

brainly.com/question/690070

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The correct question is given below:

To the nearest dollar, what does the analyst believe the value of the stock will be at the end of three weeks? (Note: Disregard the $ sign when gridding your answer.)

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A dozen eggs cosy $1.32 at the grocery store .how much profit would a restaurant make if the sold 1 scramble egg for 99 cent

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What we know: A dozen costs 1.32; there are 12 in a dozen.
What we need to know: How much a restaurant makes selling 1 egg at 0.99.
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1.32 / 12 = 0.11 <-- The cost per egg is 11 cents. To find the profit of the restaurant, just subtract the cost from the price they sell it for:
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MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

<u>Given functions</u>:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

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1 year ago