Question

3. How do the values of the 7s in the puffin

Answer 1

Answer:

The value of the "$\texttt{7}$" in $17.5$ is $100$ times the value of the "$\texttt{7}\!$" in $25.47$.

Step-by-step explanation:

Subtract $7$ from $17.5$ would turn the "$\texttt{7}$" in $17.5\!$ into a "$\texttt{0}$":

$\begin{array}{ccccc} & 1 & 7 & . & 5 \\ - & & 7 & & \\\cline{1-5}\\[-1em] & 1 & 0 & . & 5 \end{array}$.

Thus, the value of the $\texttt{7}$ is just $7$.

Turning the "$\texttt{7}$" in $25.47$ into a "$\texttt{0}$" requires subtracting $0.07$ from that number. Thus, the value of the "$\texttt{7}\!$" in $25.47\!$ would be $0.07\!$:

$\begin{array}{cccccc} & 2 & 5 & . & 4 & 7 \\ - & & 0 & . & 0 & 7 \\\cline{1-6}\\[-1em] & 2 & 5 & . & 4 & 0\end{array}$.

Hence, the value of the "$\texttt{7}$" in $17.5$ is $(7 / 0.07) = 100$ times the value of the "$\texttt{7}\!$" in $25.47\!$.