Hi :)
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Let's insert 10 for x and 5 for y and see where we end up with a true statement
y=-5+x
13x+y=135
5=-5+10
13(10)+5=135
5=5
130+5=135
5=5
135=135
So here we have two true statements
So (10,5) is definitely a solution to this system
Let's try the other options
2(10)+2(5)=30
20+10=30
30=30
4(10)+5(5)=71
40+25=71
65≠71
Remember, an ordered pair is only considered a solution if it makes both equations in the system true.
x=-37+3y
10=-37+3(5)
10=-37+15
10≠-22
We already know that (10,5) is not a solution to this system, since it made the first equation false
2x=14+y
2(10)=14+5
20≠19
We already know that (10,5) is not a solution to this system, since it made the first equation false
So the answer's A
I hope that helps