Think it would be C, not 100% on this.
Answer:
The genotypes of the rooster and the chicken are homozygous and that of their offspring is heterozygous.
This case is called codominance, where the offspring receives an allele from each parent, from the rooster and the hen, because there is codominance, so neither allele is recessive and the phenotype of both alleles is expressed so the phenotype of the offspring is checkered.
We can say then that the chicken and the rooster have equal strength between their alleles. in the cases of codominance the laws of mendel do not apply.
Answer:
Lactose is more likely to be utilised by E. Coli than Arabinose because Lactose will yield more energy (ATP) and lactose breakdown will give glucose and galactose and these will enter into the glycolytic pathways to pyruvate for ATP generation until Arabinose which will undergo Pentose phosphate pathway and this does not produce enough energy.
