Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
1 answer:
The value of the cosine ratio cos(L) is 5/13
<h3>How to determine the cosine ratio?</h3>The complete question is added as an attachment
Start by calculating the hypotenuse (h) using
h^2 = 5^2 + 12^2
Evaluate the exponent
h^2 = 25 + 144
Evaluate the sum
h^2 = 169
Evaluate the exponent of both sides
h = 13
The cosine ratio is then calculated as:
cos(L) = KL/h
This gives
cos(L) =5/13
Hence, the value of the cosine ratio cos(L) is 5/13
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Answer:
See below for answer and explanations (as well as an attached graph)
Step-by-step explanation:
Pay attention to the behavior of the asymptotes. If the asymptotes are approaching a certain x-value or y-value, then that value is undefined for the function.
Take for example :
- As x approaches ∞ and -∞, then y approaches 0, which is our horizontal asymptote
- As y approaches ∞ and -∞, then x approaches 0, which is our vertical asymptote
See the graph for a visual.
