All categories

1 year ago

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.

Mathematics

1 answer:

anzhelika [568]1 year ago

3 0

Answer:

k > 12

Step-by-step explanation:

If a quadratic equation has no real roots the values of b^2 - 4ac

( for the general form ax^2 + bx + c = 0) is negative,

So we have the inequality:

(-12)^2 - 4*3* k < 0

144 - 12k < 0

12k > 144

k > 12

You might be interested in

Given that f(x) = x2 + 12x + 32 and g(x) = x+ 4, find (f - g)(x) and

frosja888 [35]

Answer:

x²+11x+28

Step-by-step explanation:

(f - g) (x) = f(x) - g(x)

x² + 12x + 32 - (x + 4) = x² + 11x + 28

6 0

2 years ago

I need help on this question can anyone explain to me the answer?

raketka [301]

Answer:

Option C, $y = \frac{1}{10} x+1$

Step-by-step explanation:

We can find the correct answer by plugging in the x and y values of a point on the graph into each option, then finding the one that gives a true statement as a result.

For example, one point on the graph is (30,4). We can substitute 30 for the x and 4 for the y in option C's equation, $y = \frac{1}{10} x+1$ . Then, simplify:

$y = \frac{1}{10} x+1\\4 =\frac{1}{10} (30)+1\\4 = \frac{30}{10} +1\\4 = 3 +1\\4 = 4$

4 does equal 4, so when we substitute a point from the graph into this equation, the result is a true statement. Thus, option C is the answer.

4 0

2 years ago

Consider the right triangle ABC given below:

frez [133]

Can you please provide the image of the triangle. thank you:)

4 0

2 years ago

Read 2 more answers

Please please help me and fast

Eduardwww [97]

Its 12. Part a was 2 part b was 3
6×2=12
4×3=12

4 0

2 years ago

Which inequality is represented by the graph

castortr0y [4]

Well, accordingly to the graph, it has a positive slope so we can eliminate b and d. So it is either a or c. As x increases, so does y. Y is almost not quite equal to 3x-2. In fact, it is greater, so I'd go with A. I'm pretty confident.

8 0

2 years ago

Read 2 more answers

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.​

Find the set of values of k for which the equation 3x² - 12x + k >. 0 has no real roots.