The histogram shows the distribution of minting year for a sample of
1 answer:
All the parts of the questions about the given histogram have been answered below.
<h3>What is a histogram?</h3>- A histogram is a graph that depicts the frequency of numerical data using rectangles.
- The vertical axis of a rectangle represents the distribution frequency of a variable (the amount, or how often that variable appears).
(A) The distribution of minting year:
According to the histogram, the distribution of minting years is 1900-1910 and 1940-2020.
(B) The median:
Add the two middle numbers together and divide them by two to get the median.
10 + 15 / 2 = 12.5
So, the median is somewhere between 10-15.
(C) The range:
The range is computed by subtracting the lowest and highest values.
25 - 0 = 25
So, the range is 25.
(D) The potential outliers:
According to the histogram, the potential outliers are 1910-1940.
Therefore, all the parts of the questions have been answered.
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Answer:
82
Step-by-step explanation:
We are given that a graph which shows the number of beads used for varying cord lengths.
The graph
We have to find the number of beads that she can used for cord length 32 in.
Substitute the value x=32
Then, we get
After round to unit place then, we get
y=82
Hence, the best estimate she can used for number of beads =82
Answer: 82
9514 1404 393
Answer:
- e ≈ 9.608
- D ≈ 46.5°
- F ≈ 38.5°
Step-by-step explanation:
The only given angle is between the two given sides, so the Law of Cosines must be used to find the side opposite the angle. It tells you ...
e² = d²+f² -2df·cos(E)
e² = 7² +6² -2·7·6·cos(95°) ≈ 92.321082
e ≈ 9.608
The remaining angles can be found from the law of sines.
sin(D)/d = sin(E)/e
D = arcsin(d/e·sin(E)) ≈ arcsin(7/9.608·sin(95°)) ≈ 46.5°
F = 180° -95° -46.5° = 38.5°
