Well obviously quarters equal 25 cents. So you have to divide the 8.85 by 25 first. That means he could have 35 quarters. That least the rest as being dimes. So find the remaining amount of the 8.85. If you have 35 quarters that's $8.75. And 8.85 minus 8.75 is 10 cents. which would be 2 nickels. That only adds up 37 coins. So you break down one of the 25. That would mean 5 more coins could be nickels. Add 37 and 5 to get 42. Do it again. 25 cents in nickels would be 5 more coins. would be 46. that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters. So you can do it one more time. 32 quarters means there is $8 in quarters at this point.
Now add you have 12 nickels, and you made 5 more. That's 17 nickels. That equals 85 cents. So add 17 and 32 to be sure you have 49 coins, which you do.
So 17 nickels, 32 quarters to equal 49 coins and $8.85
(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
The correct answer is 720 I did this problem long time ago hope this helps :)
Answer:
I don't speak Spanish
Step-by-step explanation:
The weight of each cabbage is not given.
I'll assume that each cabbage weighs p pounds.
Now, we know that Yasmin bought 6 cabbage each weighing p pounds. To know the total weight, we will simply multiply the number of cabbages by the weight of each as follows:
Total weight = 6 * p = 6p pounds
Hope this helps :)
Answer:
The standard deviation of weight for this species of cockroaches is 4.62.
Step-by-step explanation:
Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
To find : What is the approximate standard deviation of weight for this species of cockroaches?
Solution :
We have given,
Mean 
The sample mean x=55
A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.
i.e. P(X>55)=14%=0.14
The total probability needs to sum up to 1,
The z-score value of 0.86 using z-score table is z=1.08.
Applying z-score formula,
Where, 
is standard deviation
Substitute the values,
The standard deviation of weight for this species of cockroaches is 4.62.
