In order for the mode to be 6, there must be more of them than any other number. In order for the mean to be 3.5, most of the distribution must lie at 3 or below to balance the large number of 6s. For the median to be 3, there must be as many scores at or above 3 as at or below 3. Thus, we choose to have most of the distribution with values 1, 2, 3 and only enough 6s to make that be the mode.
I believe 9 students rides the bus
3/8 x 24= 9
C^2=a^2+b^2-2abcosC
13^2=10^2+11^2-2×10×11×cos(°)
169=100+121-220cos(°)
220cos(°)=100+121-169
220cos(°)=52
cos(°)= 13/55
°=cos-1(13/55)
°=76.328°
Answer: 60.93 < μ < 69.07
Step-by-step explanation: The true mean of a set of data is between an interval of values with a percentage of precision, e.g., a <u>99% confidence interval</u> means we are 99% confident the true mean is between the lower and upper limits.
To find the interval, use
x±
z is z-score related to the % of confidence level
In this case, a 99% confidence interval is 2.576
x is sample mean
Calculating:
x = 65
65±
65±4.07
Confidence Interval: 60.93 < μ < 69.07
Meaning that we are 99% sure the population means is between 60.93 and 69.07.