1000 khz am radio station broadcasts with a power of 20 kw number of photon emitted per second is 30.16 x 10^30 photon/s.
The frequency of the radio station is:
f
=
1000
k
H
z
=
1
×
10^6Hz
The transmit power is: P = 20kW = 20 X 10^3 W
The transmit power is: h = 6.63 x 10 ^-34 m^2.kg/s
The number of photon emitted per second = N = P/hf = <u>30.16 x 10^30 </u>photon/s.
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F=mv^2/R
----> V^2=FR/m=(350x0.9)/2.5=126
----- V=11.22 m/s
Answer:
Current = 10 Amperes.
Explanation:
Given the following dat;
Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C
Time = 1 hour to seconds = 60*60 = 3600 seconds
To find the current;
Quantity of charge = current * time
Substituting in the equation
36000 = current * 3600
Current = 36000/3600
Current = 10 Amperes.
Answer:
Hits per second=199 hit/s
Explanation:
#Given the angular velocity, , radius of the record and the distance between any two successive bumps on the groove as .
The linear speed of the record in meters per second is:
#From above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:
Hence the bumps hit the stylus at around 199hit/s
It would have to be cardio i think not totally sure