Answer:
Step-by-step explanation:
Final concentration % = [grams of salt / mililiters of solution] * 100
grams of salt = grams of salt from solution 1 + grams of salt from solution 2
grams of salt from solution 1 = mililiters * %/100 = 80 mililiters * 0.25 g/mililiters = 20 g
grams of salt from solution 2 = mililiters *%/100 = x*0.10 g/mililiters = 0.1x
mililiters of final solution = mililiters from solution 1 + mililiters from solution 2
mililiters of final solution = 80 mililiters + x mililiters
=> Final concentration, % = [0,10x + 20 g] / [x + 80 mililiters] * 100
the answer to this is
the two is for the top of the five 2
-3(x - 5) +23
Step-by-step explanation:
Key : Plug in the numbers given in the parenthesis into the x values of the corresponding functions.
f(1/2) = 1/ 1/2 - 4 = 1/-7/2 = -2/7
g(1/2) = 1/1/2 - 2 = -3/2
f(-1/4) = 1/-1/4-4 = 1/-17/4 = -4/17
g(-1/4) = 1/-1/4 - 2 = 1/-9/2 = -2/9
Answer:
C: 3/4
Step-by-step explanation:
Hopefully this helps!
Answer:
Step-by-step explanation:
(a) What is the mean fish weight of your catch of 6? Round your answer to 1 decimal place. =Total weight/no of fish in sample
_
_____ pounds
(b) If 6 bass are randomly selected from Clear Lake, find the probability that the mean weight is greater than the mean of those you caught. Round your answer to 4 decimal places.
___P(mean >2.65)=
_____
Sample mean follows a normal distribution with mean = 2.2 and std error = 0.6/sqrt 6
(c) Which statement best describes your situation?
_____ This is not particularly unusual because the mean weight of your fish is only 0.5 pounds above the population average.
