A shape has an area of 37 mm², of which 60%
1 answer:
If the side are increased by 45% then the area of green part will be 26.6955 .
Given that area of a shape of 37 in which 60% is green.
We are required to find the area of green region if the side is increased by 45%.
Area is basically part of a surface covered by a shape.
When the side is increased by 45% then the area will increase by 45%*45%=20.25%.
Increased area =37*20.25%=7.4925
New area=37+7.4925
=44.4925
We have been given that 60% is the area of green.
Area of green region=44.4925*60/100
=26.6955
Hence if the sides are increased by 45% then the area of green part will be 26.6955 .
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Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
