Answer:
The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg
Explanation:
From the formulae
F = qvB and F = mv²/r
Where F is Force
q is charge
v is speed
B is magnetic field strength
m is mass
and r is radius
Then,
qvB = mv²/r
qB = mv/r
We can write that
q/m = v/rB ---- (1)
Also
From Electric force formula
F = Eq
Where E is the electric field
and magnetic force formula
F = Bqv
Since, electric force = magnetic force
Then, Eq = Bqv
E = Bv
∴ v = E/B
Substitute v = E/B into equation (1)
q/m = (E/B)/rB
∴ q/m = E/rB²
(NOTE: q/m is the charge to mass ratio)
From the question,
E = 3.10 ×10³ N/C
r = 4.20 cm = 0.0420 m
B = 0.360 T
Hence,
q/m = 3.10 ×10³ / 0.0420 × (0.360)²
q/m = 569517.9306 C/kg
q/m = 5.7 × 10⁵ C/kg
Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.
Answer:
The velocity of the ball after 5 seconds will be 49 m/s
Explanation:
<em>v = final velocity</em>
<em>u = initial velocity</em>
<em>g = acceleration due to gravity</em>
<em>t = time</em>
Initial velocity of the ball = 0 (As the ball is dropped from rest )
Acceleration due to gravity = 9.8 m/s
Time taken = 5 sec
As the acceleration due to gravity is constant in both the cases we can use the equations of motion in order to solve this question
Part I :- As we already know the values of u,g,ant t we can use the first equation of motion in order to find v
Part II :- As we know the values of u, t , g we can use the second equation of motion in order to find s.
Velocity of the ball after 5 seconds
Distance covered by the ball in 5 sec
'Newton-second' is dimensionally equivalent to 'kilogram-meter/second'.
I don't have research to back it up, but exercise is working out. Fitness is taking care of your body, that includes working out and things like eating right.
The force of gravity is much weaker than the strong nuclear force. But the strong nuclear force only acts over short distances, such as within the nuclues. The gravitational force can act over infinite distance.
