A sample of gas occupies 575 ml at 1.50 atm and 125 degrees Celsius. If the temperature is changed to 20 degrees Celsius and the volume is changed to 0.300 L. The will be a new pressure at 2.12 atm.
Temperature is the measure of hotness or coldness expressed in phrases of any of numerous scales, including Fahrenheit and Celsius. Temperature shows the route wherein heat energy will spontaneously waft—i.e., from a hotter frame (one at a higher temperature) to a less warm body (one at a decreased temperature).
The common body temperature is ninety-eight.6 F (37 C). however normal frame temperature can vary between ninety-seven F (36.1 C) and 99 F (37.2 C) or more. Your frame temperature can range depending on how active you are or the time of day.
The heat of an item is the entire strength of all of the molecular motion interior of that item. Temperature is the degree of the thermal energy or average warmth of the molecules in a substance. SI Unit
V₁ = 0.575L
P₁ =1. So atm.
T₁ =125 + 273=398 k
√2 =0.300 L
P₂ =?
T₂ = 20 +273= 293K
P1XV 1=T2
1.50 X 0.575 lit=398 K
P2 x 0.300 lit =293K
1-50 atm x 293KX 0.575 lit
0. 300 lit X 396 K
P₂ =2.1165 atm
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Answer:
The bond that should pay the highest interest rate is:
d. a bond issued by a new restaurant chain.
Explanation:
This is based on the fact that the new restaurant chain is untested, has higher risk profile and the bondholders are assuming higher risks, and the bond cannot be compared to the bonds issued by the US government, New York State, and General Motors, in that order. The new restaurant chain will be offering a higher rate of return than others because it is new to the bond market and would like to attract potential bond investors. Without the higher rate, therefore, it will not be successful in the bond issuance.
3000 (1+0.051)^(t)=2000 e^(0.075t)
Solve for t using Google calculator
To get
T=16.05 years
Answer:
b. $4,908,000
Explanation:
According to the FASB GAAP, the straight line method is used in this given question which is shown below:
= (Original cost - residual value) ÷ (useful life)
= ($40,900,000 - $4,090,000) ÷ (15 years)
= ($36,810,000) ÷ (15 years)
= $2,454,000
In this method, the depreciation is same for all the remaining useful life
For two years, the accumulated depreciation would be
= Annual year depreciation × number of years
= $2,454,000 × 2 years
= $4,908,000
