Step 1: Subtract -2 from both sides.<span><span><span><span>
m2</span>+<span>4m</span></span>−<span>(<span>−2</span>)</span></span>=<span><span>−2</span>−<span>(<span>−2</span>)</span></span></span><span><span><span><span>
m2</span>+<span>4m</span></span>+2</span>=0</span>
Step 2: Use quadratic formula with a=1, b=4, c=2.<span>
m=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
m=<span><span><span>−<span>(4)</span></span>±<span>√<span><span><span>(4)</span>2</span>−<span><span>4<span>(1)</span></span><span>(2)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>
m=<span><span><span>−4</span>±<span>√8</span></span>2</span></span><span><span>
m=<span><span>−2</span>+<span><span><span>√2</span><span> or </span></span>m</span></span></span>=<span><span>−2</span>−<span>√2</span></span></span><span>
</span>
The polynomial whose zeroes are 1, 2 and 3 is given by,
(x-1)(x-2)(x-3) = 0
(x-1)[x²-3x-2x+6]=0
(x-1)[x²-5x+6]=0
x[x²-5x+6] -1[x²-5x+6]=0
x³-5x²+6x-x²+5x-6=0
x³-6x²+11x-6=0
Therefore, the required polynomial is,
x³ - 6x² + 11x -6 = 0
Answer:
7. MN = 12
8. m<XYZ = 90°
9. m<YXM = 49°
10. m<XWZ = 131°
Step-by-step explanation:
This drawing is messed up.
The perspective is off because <NMW looks to be an obtuse angle because it appears to be greater than a square angle or 90°.
The median should be accurate in perspective even though WZ appears to be greater than MN or XY which is greater than WZ but appears to be smaller than WZ.
