All categories

1 year ago

What is the coefficient for oh−(aq) when s2−(aq) no3−(aq) → s(s) no(g) is balanced in basic aqueous solution?

Chemistry

1 answer:

omeli [17]1 year ago

5 0

From the balanced redox equation of the reaction, the coefficient of OH⁻ is 8.

<h3>What is the balanced redox equation of the reaction?</h3>

A redox equation is the equation of a redox reaction in which oxidation and reduction occurs simultaneously.

The given redox reaction takes place in a basic solution

The balanced redox equation of the reaction is given below:

4 H₂O(l) + 3 S²⁻(aq) + 2 NO₃⁻(aq) ---> 3 S(s) + 2 NO + 8 OH⁻(aq)

In conclusion, a redox equation is balanced when oxidation and reduction occur to the same extent.

Learn more about redox equations at: brainly.com/question/26750732

#SPJ1

You might be interested in

IS IT BETTER OR WORSE TO WORKOUT/EXERCISE IN DARK OR LIGHT COLORED CLOTHING?

soldi70 [24.7K]

Answer:

Dark clothing

Explanation:

Dark clothing like black absorbs/locks in heat. Since exercise is to burn and tonify our body from unwanted fat it is important to sweat. This is where heat comes in and helps you sweat

3 0

2 years ago

Read 2 more answers

I NEED HELP PLEASE ASAP! BRAINLIEST :)

Keith_Richards [23]

Answer:

6. d

7.c

8.a

9.b

Explanation:

For 6, the answers are not particularly close to 100, and they are not clustered much. For 7, the answers are all clustered very close to 100. For 8, the answers are clustered closely, but not close to 100. For 9, the answers are close to 100, but not clustered very tightly. Hope this helps!

6 0

2 years ago

If molar mass of M(OH)3 = 78 8. mass of M

Cerrena [4.2K]

Answer:

From molar mass=total RAM of each individual element

78.8=(16+1)×3+M

78.8-51=M

27.8g/mol=M

5 0

2 years ago

A flask holds 3.01 x 1023 molecules of carbon dioxide. The container is holding ________

sammy [17]

(B), because 1.0 moles would be 6.02 x 10^23 molecules. So you have half a mole.

8 0

2 years ago

Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.

Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) Trypsin

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) Chymotrypsin

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the "Lis" and "Arg" (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the "Phe" (See figure 2). The second amino acid that can be broken is tyrosine, but this amino acid is placed in the C terminal spot, therefore will not be involved in the hydrolysis.

3 0

2 years ago