Answer:
35.5450 will be rounded to 35.55
Explanation:
=35.5450
if the last digit is less than 5 then it will be ignored
=35.545
when the dropping digit is 5 then the retaining digit will increse by a factor of 1
=35.55
i hope this will help you
<span>They are composed of cells</span>
The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
The energy of the photon is given by;
E = hc/λ
E = energy of the photon
h = Plank's constant
c = speed of light
λ = wavelength of light
For the upper boundary range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 270 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 270 × 10^-9
E = 7.33 × 10^-19 J
For the lower range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ =300 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 300 × 10^-9
E = 6.6 × 10^-19 J
Hence, the energy range 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
Learn more: brainly.com/question/24857760
Answer:
Explanation:
Well the gas is the fuel for the flame of course. The collision theory comes into play when the gas turns on, chemicals collide with one another. Then reactions occur causing the flame. Then when you take away the fuel, the flame stops because there is no atoms or molecules to come together/collide with one another.
Sorry if its wrong or doesn't make sense... Wish you the best of luck on whatever your doing!
Answer:
![\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctext%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
Explanation:
At the beginning, you have two reactions happening:
As you add KOH(aq), it does two things:
- It increases the volume of the solution.
- It reacts with the hydronium ions to form water.
A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.
B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.
C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.
D) As HClO₂ reacts, it forms ClO₂⁻. ![\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctextbf%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
