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1 year ago

Find all the missing values to make the equation true

Mathematics

1 answer:

Georgia [21]1 year ago

4 0

The missing value in the logarithm are as follows:

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ 28
log₆ 1 / 81 =
- 4 log₆ 3

<h3>How to solve logarithm?</h3>

Using logarithm rule,

logₐ b - logₐ c = logₐ (b / c)

logₐ b + logₐ c = logₐ (b × c)

Therefore,

log₃ 7 - log₃ 2 = log₃ (7 / 2)

log₉ 7 + log₉ 4 = log₉ (7 × 4) = log₉ 28

log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ = - 4 log₆ 3

learn more on logarithm here: brainly.com/question/24515212

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Step-by-step explanation:

Given

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2 years ago

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Find the value of x so that the function has the given value.

nataly862011 [7]

For h(x) = -7x + 10, x =1

For r(x) = 4/5x+ 7 , x = -15

Step-by-step explanation:

in order to find the value of x on which the functions will have given values, we will put the functions equal to the given values

So,

$h(x) = -7x+10\\3 = -7x+10\\3-10 = -7x+10-10\\-7 = -7x$

Dividing both sides by -7

$\frac{-7x}{-7} = \frac{-7}{-7}\\x = 1$

$r(x) = \frac{4}{5}x +7\\-5 = \frac{4}{5}x +7\\-5-7 = \frac{4}{5}x\\-12 = \frac{4}{5}x\\x = -12 * \frac{5}{4}\\x = -15$

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Keywords: Functions

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2 years ago