Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4
<em><u>Solution:</u></em>
Let "a" be the age of Alex
Let "g" be the age of George
Let "c" be the age of Carl
<em><u>Alex is 12 years older than George</u></em>
Therefore,
Age of Alex = 12 + Age of George
a = 12 + g
g = a - 12 ---- eqn 1
<em><u>Carl is Three times older than Alex</u></em>
Age of Carl = 3 x Age of Alex
c = 3a -------- eqn 2
<em><u>The sum of their ages is 68</u></em>
age of Alex + age of George + age of Carl = 68
a + g + c = 68 ----------- eqn 3
<em><u>Substitute eqn 1 and eqn 2 in eqn 3</u></em>
a + a - 12 + 3a = 68
5a - 12 = 68
5a = 12 + 68
5a = 80
a = 16
<em><u>Substitute a = 16 in eqn 2</u></em>
c = 3(16) = 48
c = 48
<em><u>Substitute a = 16 in eqn 1</u></em>
g = 16 - 12 = 4
g = 4
<em><u>Find the ratio of George’s age to Carl’s age to Alex’s age</u></em>
Ratio of George’s age to Carl’s age to Alex’s age = g : c : a
g : c : a = 4 : 48 : 16
Divide the above ratio by 4 to reduce to lowest terms
g : c : a - 1 : 12 : 4
Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4