The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.
where,
- i: van 't Hoff factor (1 for non-electrolytes)
- Kf: cryoscopic constant
- m: molality
The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
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Answer:
D
Explanation:
i took the test and got it right :)
Answer:
Answer is B.
Explanation:
Hydrogen bonds forms when hydrogen atom is attracted towards oxygen atom of other water. A proton is shared by two ion electrons pair in which oxygen atom is partially negatively charged while hydrogen atom is partially positively charged.
Answer:
0.045 L or 45 mL
Explanation:
Moles = Mass/M.Mass
Moles = 10 g / 109.94 g/mol
Moles = 0.09 moles
Also,
Molarity = Moles / Vol in L
Or,
Vol in L = Moles / Molarity
Vol in L = 0.09 mol / 2 mol/L
Vol in L = 0.045 L
Answer:
It is called Ionization Energy.