The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release
1 answer:
The mass of melted gold to release the energy would be 3, 688. 8 Kg
<h3>How to determine the mass</h3>We have quantity of energy is;
Q = n × HF
n = number of moles
HF = heat of fusion
Let's find number of moles
235.0 = n × 12.550
number of moles = = 18. 725 moles
Note that molar mass of Gold is 197g/ mol
Number of moles = mass/ molar mass
Mass = number of moles × molar mass
Mass = 18. 725 × 197
Mass = 3, 688. 8 Kg
Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg
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Answer:
thats all help me too:)...............
Answer : The mass of oxygen formed must be 3.8 grams.
Explanation :
Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The balanced chemical reaction will be,
According to the law of conservation of mass,
Total mass of reactant side = Total mass of product side
Total mass of = Total mass of
As we are given :
The mass of = 25.3 grams
The mass of = 23.4 grams
So,
Therefore, the mass of oxygen formed must be 3.8 grams.