1 year ago

Prove that cos1° cos2° cos3°...cos180° = 0

Mathematics

1 answer:

leva [86]1 year ago

4 0

Answer:

I don't know‍♀ sorrry bro

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Step-by-step explanation:

Given : a=7 b=10 and C is a right triangle

solution :

refer the attached figure .

Since ΔACB is right angled triangle so we will use trigonometric ratios .

$tan\theta=\frac{perpendicular}{base}$

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Base=a=7

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$B=55.00797173^{\circ}$

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Prove that cos1° cos2° cos3°...cos180° = 0​

Prove that cos1° cos2° cos3°...cos180° = 0