The vertex of the equation is ( -2 , -2 )
The axis of symmetry is x= - 2
<span> |2x − 5| − 2 = 3
</span><span>1) |2x − 5| = 3 +2
2)</span><span> |2x − 5| = 5
3) 2x-5 = 5, or 2x-5= -5
4)2x=10, or 2x=0
5) x = 5 , or x = 0
Check:
</span> |2x − 5| − 2 = 3
|2*5− 5| − 2 = 3 or |2*0 − 5| − 2 = 3
|5|-2=3 or |-5| -2 =3
3=3 (true) or 3=3 (true)
All steps are correct.
A stem and leaf plot shows sets of two digit numbers, by separating the ten’s place and the one’s place. On the left is the different ten’s values, while on the right next to each of the values on the left is the one’s values that associate with each of the ten’s values. This means that the numbers in this set of data are 32, 47, 51, 55, 55, 55, 58, 64, and so on. From there, you can use that knowledge to figure out how many scores were above 60.
The terms that are above 60 are 64, 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, and 99, for a total of 13 of the 20 scores being above 60.
Answer:
Step-by-step explanation:
There are no categorical antonyms for eleven. The numeral eleven is defined as: The cardinal number occurring after ten and before twelve.
Let that be
Two vertical asymptotes at -1 and 0
If we simply
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is
Graph attached