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1 year ago

5. Write the following inequality in slope-intercept form. −8x + 4y ≥ −52 y ≤ 2x − 13 y ≥ 2x − 13 y ≤ 2x + 13 y ≥ 2x + 13

Mathematics

1 answer:

coldgirl [10]1 year ago

8 0

Answer:35443

Step-by-step explanation:

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Select the expressions that are equivalent to 10 + 2x + 5y + 3x.

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2 years ago

Factorise fully 7g - 56

Kobotan [32]

Answer:

7 (g-8)

Step-by-step explanation:

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4 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

2 years ago

A national study reported that 75% of high school graduates pursue a college education immediately after graduation. A private h

Verdich [7]

Answer:

The % students going to higher education is 79.60 % which is higher than the reported value.

Step-by-step explanation:

According to national study report the students going to college for higher education = 75 %

Given that

156 of their 196 graduates last year went on to college.

% students going to higher education is

$(\frac{156}{196}) 100 = 79.60$

Thus the % students going to higher education is 79.60 % which is higher than the reported value.

4 0

3 years ago

Help me plzzzz...... .

Vlada [557]

x = 4.5 so it is 3/-8 = 4.5/12

7 0

2 years ago

Read 2 more answers