I actually just learned this. I think this is the right answer.
{f(x)=2x+1 g(x)=x2+2x−8
1 answer:
The value of g(x) = 2[f(x)]² - 1 is g(x) = 8x² + 8x + 1
<h3>How to find a function?</h3>f(x) = 2x+1
Find
g(x) = 2[f(x)]² - 1
Hence,
g(x) = 2[2x + 1]² - 1
g(x) = 2[4x² + 4x + 1] - 1
g(x) = 8x² + 8x + 2 - 1
g(x) = 8x² + 8x + 1
learn more on function here: brainly.com/question/1442153
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I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The terms cancel, leaving you with
and the limand is continuous at , so we can substitute it to find the limit has a value of -1/18.