Answer:
A. (f-g)(x) = -7x -3
Step-by-step explanation:
(f -g)(x) = f(x) -g(x) = (-3x -5) -(4x -2)
= -3x -5 -4x +2
= -3x -4x -5 +2
(f -g)(x) = -7x -3
Answer:
First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Step-by-step explanation:
Let First integer = n
Second Integer = n+1
Third Integer = n+2
According to the question given (If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third) the equation will be:
138 - n = (n+1) + (n+2)
Solving the equation:
138 - n = n+1+n+2
138 - n = 2n+3
138 - 3 =2n +n
135 = 3n
135/3 = n
=> n= 45
So, First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Answer:
B. (2/3) x (2/3) x (2/3)
C. 8/27
D. 2^3 /3^3
Step-by-step explanation:
You need to know the following property
Exponent also means you're multiplying the same number for an 'n' number of times.
For example, 2^3 = 2 * 2 * 2
we multiply it by itself 3 times since 3 is the exponent.
x^y
x is the base, y is the exponent
we read it as x to the power of y
If the exponent is 2, we say it as x squared
If the exponent is 3, we say it as x cubed