What is the minimum volume of 5.50 M HCl necessary to neutralize completely the hydroxide in 718.0 mL of 0.183 M NaOH
1 answer:
The volume of HCl required is 23.89 mL
Calculation of volume:
The reaction:
As HCl and NaOH react in 1 : 1 ratio.
Volume of NaOH= 718 mL
Concentration= 0.183M
Volume of HCl= ?
Concentration= 5.50M
Using the dilution formula:
Therefore,
Volume of HCl required will be 23.89 mL.
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