I believe 10.42 if you add try this if its not on their try dividing by 2
<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Linear is 4
Quadratic is 2
Cubic is 3
Good evening ,
Answer:
<h2>x = 3 or x = -21</h2>
Step-by-step explanation:
x²+18x=63 ⇌ x²+18x+81 = 63 + 81
⇌ (x+9)² = 144 ⇌ (x+9)² = 12² ⇌ (x+9-12)(x+9+12) = 0
⇌ (x-3)(x+21) = 0
⇌ x=3 or x=-21.
:)