i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer:
15/100
Step-by-step explanation:
Answer:
8x + 16y = 39 and
40x + 8y = 42
Step-by-step explanation:
Let the length of the blue tiles is b inches and that of the white tiles is w inches.
So, given that a row of 8 blue tiles and 16 white tiles has a length of 39 inches and a row of 40 blue tiles and 8 white tiles has a length of 42 inches.
Therefore, we can write the system of linear equations that represents the relationship between the length if a blue tile and a white tile in inches as
8x + 16y = 39 and
40x + 8y = 42 (Answer)
72 divides by 9 is 8 so 2 times 8 is sixteen so that would be the answer
Answer:
Step-by-step explanation:
If W is between X and Y, this means that W is the midpoint of X and Y. The expression XW+WY = XY is therefore true.
Given WX = 6n - 10, XY = 17, and WY = 3n, substituting the given functions into the formula;
6n-10+3n = 17
9n-10 = 17
add 10 to both sides
9n-10+10 = 17+10
9n = 27
divide both sides by 9
9n/9 = 27/9
n = 3
Since WX = 6n-10
substitute n = 3 into the function
WX = 6(3)-10
WX = 18-10
WX = 8
<em>Hence n = 3 and WX = 8</em>