Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
<h3>3.1°C</h3>
<em />
The full decimal is 2.59328...
When you round up the answer is 2.6 atoms of Li
Surface tension
..viscosity is the thickness of a liquid, doesn't fit here...condensation and evaporation are processes not properties.
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
<h3>What is precipitate?</h3>
Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is
2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
Learn more about precipitate.
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6 . 2 in its inner shell & the remaining 6 in its outer shell.