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1 year ago

12

Find the value of b.

1 answer:

Nesterboy [21]1 year ago

7 0

Answer: $230^{\circ$

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume $\overline{AB}$ and $\overline{BC}$ are tangents to the circle.

$\overline{BO} \cong \overline{BO}$ (reflexive property)
$\overline{AB} \cong \overline{BC}$ (tangents drawn from a common external point are congruent)
$\angle BAO \cong \angle BCO$ (right angles are congruent)

Therefore, we know $\triangle ABO \cong \triangle CBO$ by HL.

Thus, by CPCTC,

$\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}$

This means the measure of minor arc AC is $130^{\circ}$ , and thus $b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}$

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sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

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$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

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$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

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2 years ago

Help me in this algebra1 problem

sergeinik [125]

X=kevin
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2 years ago

If a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter d

grin007 [14]

Answer:

The diameter decreases at a rate of 0.053 cm/min.

Step-by-step explanation:

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The surface area of an snowball has the following equation:

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In which d is the diameter.

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To solve this question, we differentiate the equation for the surface area implictly, in function of t. So

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2 years ago