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1 year ago

I need help with this problem. x3+4x

Mathematics

1 answer:

Yuki888 [10]1 year ago

6 0

Answer: x=0 x=2i x=-2i

if your factoring: x(x^2+4)

Step-by-step explanation:

(if your solving for x)

$x^{3} +4x\\x(x^{2} +4)\\\\x=0\\\\x=\frac{-b}{2a}\frac{+}{-} \frac{\sqrt{b^2-4ac}}{2a} \\\\x=\frac{0}{2}\frac{+}{-} \frac{\sqrt{0^2-16}}{2} \\x={0}}\frac{+}{-} \frac{\sqrt{-16}}{2} \\$

$x={0}}\frac{+}{-} \frac{4i}{2} \\\\\\x=\frac{+}{-}2i$

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How do you find the range of 0.3 0.9 0.2 0 0.7 0.9 0.4

Gelneren [198K]

1) order them from least to greatest. (0.2, 0.3, 0.4, 0.7, 0.9, 0.9)
2) Take the largest number and smallest number and find the difference. 0.9-0.2=0.7
3) answer is 0.7

3 0

2 years ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

2 years ago

HELP PLZ DUR 11;59 plz help me

Norma-Jean [14]

Answer:

Base = 10 cm

Height = 60 cm

Step-by-step explanation:

The formula for the area of a triangle is $area=\frac{1}{2} *b*h$ , where <em>b</em> is the length of the base of the triangle, and <em>h</em> is the length of the height of the triangle.

We know the area is 300, and since the height of the triangle is 6 times its base, we know that $h=6*b$ . We can plug in these values into our formula for the area of a triangle, which gives us the following equation to solve:

$300=\frac{1}{2} *b*(6*b)$

$3b^2=300$

$b=\sqrt{100} =10$

The base of the triangle is 10 centimeters.

Now that we know the base of the triangle, we can plug its value in to the original formula to solve for the height of the triangle, which gives us the following equation:

$300=\frac{1}{2} *10*h$